Multiple Integrals
Multiple Integrals
$$\iint_R f(x,y)\,dA = \int_a^b \int_{g_1(x)}^{g_2(x)} f(x,y)\,dy\,dx$$
Gives the volume under the surface $z = f(x,y)$ over region $R$.
Evaluate from inside out — integrate the inner variable first, treating the outer variable as constant.
$$\iiint_E f(x,y,z)\,dV = \int_a^b\int_{g_1}^{g_2}\int_{h_1}^{h_2} f\,dz\,dy\,dx$$
Evaluate $\int_0^1 \int_0^2 (x+y)\,dy\,dx$.
Inner: $\int_0^2 (x+y)\,dy = [xy + y^2/2]_0^2 = 2x + 2$.
Outer: $\int_0^1 (2x+2)\,dx = [x^2+2x]_0^1 = 3$.
Evaluate $\int_0^1 \int_0^x x^2y\,dy\,dx$.
Inner: $\int_0^x x^2y\,dy = x^2 \cdot x^2/2 = x^4/2$.
Outer: $\int_0^1 x^4/2\,dx = \frac{1}{10}$.
Find the area of $R$: $0 \leq x \leq 2$, $0 \leq y \leq x$.
$$A = \int_0^2 \int_0^x 1\,dy\,dx = \int_0^2 x\,dx = 2$$
Practice Problems
Show Answer Key
1. $\int_0^2 \frac{9x}{2}\,dx = 9$
2. $\int_0^1(x^2+1/3)\,dx = 1/3+1/3 = 2/3$
3. $\int_0^{\pi} 1/2\,d\theta = \pi/2$
4. $\int_0^1\int_0^{x^2} 1\,dy\,dx$
5. $\int_0^1 2x\,dx = 1$
6. $\int_0^1\int_y^1 f\,dx\,dy$
7. $2 \cdot 1 \cdot 3 = 6$
8. $\int_0^1\int_0^y e^{y^2}\,dx\,dy = \int_0^1 ye^{y^2}\,dy = \frac{e-1}{2}$
9. $\int_0^1\int_0^1 (4-x^2-y^2)\,dy\,dx = 4-1/3-1/3 = 10/3$
10. $\int_0^1 y^3\,dy = 1/4$
11. The area of region $R$
12. $\int_0^2\int_0^3 xy\,dy\,dx = \int_0^2 9x/2\,dx = 9$