Partial Derivatives
Partial Derivatives
For $f(x,y)$, the partial derivative with respect to $x$ treats $y$ as a constant:
$$f_x = \frac{\partial f}{\partial x} = \lim_{h\to 0} \frac{f(x+h,y)-f(x,y)}{h}$$
Similarly $f_y = \frac{\partial f}{\partial y}$ treats $x$ as constant.
$$f_{xx} = \frac{\partial^2 f}{\partial x^2}, \quad f_{yy} = \frac{\partial^2 f}{\partial y^2}, \quad f_{xy} = \frac{\partial^2 f}{\partial y \partial x}$$
Clairaut's Theorem: If $f_{xy}$ and $f_{yx}$ are continuous, then $f_{xy} = f_{yx}$.
Find $f_x$ and $f_y$ for $f(x,y) = x^3 + 2xy - y^2$.
$f_x = 3x^2 + 2y$
$f_y = 2x - 2y$
Find $f_x$ for $f(x,y) = e^{xy}$.
$f_x = ye^{xy}$
Find $f_{xx}$ and $f_{xy}$ for $f(x,y) = x^2y + 3xy^3$.
$f_x = 2xy + 3y^3$. Then $f_{xx} = 2y$ and $f_{xy} = 2x + 9y^2$.
Practice Problems
Show Answer Key
1. $f_x = 2x+3y$, $f_y = 3x+3y^2$
2. $y\cos(xy)$
3. $\frac{1}{x^2+y}$
4. $f_x = 4x^3-4xy$; $f_{xx} = 12x^2-4y$
5. $f_{xy} = 6xy^2 = f_{yx}$ ✓
6. $\frac{y}{(x+y)^2}$
7. $f_x = 2xy$; $f_x(1,2) = 4$
8. $f_x = yz$, $f_y = xz$, $f_z = xy$
9. $2e^{x+2y}$
10. $-x^2\cos y$
11. $dz/dt = 2x(1)+2y(2t) = 2t+4t^3$
12. $f_{xx}=e^x$, $f_{yy}=0$, $f_{xy}=1$