Surface Area and Volume
Surface Area and Volume
Surface area and volume extend two-dimensional measurement into three dimensions. Surface area tells you how much material is needed to cover the outside of a solid (like wrapping a gift), while volume tells you how much space the solid occupies (like filling a container with water).
This lesson covers the formulas for prisms, cylinders, pyramids, cones, and spheres. The patterns are logical — a cone is one-third of a cylinder with the same base and height, just as a pyramid is one-third of a prism.
Learning these formulas equips you for practical problems in construction, packaging, manufacturing, and engineering.
| Solid | Surface Area | Volume |
|---|---|---|
| Rectangular Prism (box) | $SA = 2(lw + lh + wh)$ | $V = lwh$ |
| Cube | $SA = 6s^2$ | $V = s^3$ |
| Cylinder | $SA = 2\pi r^2 + 2\pi rh$ | $V = \pi r^2 h$ |
| Cone | $SA = \pi r^2 + \pi r l$ | $V = \frac{1}{3}\pi r^2 h$ |
| Sphere | $SA = 4\pi r^2$ | $V = \frac{4}{3}\pi r^3$ |
Find the volume and surface area of a box with $l=10$, $w=6$, $h=4$.
$V = 10 \times 6 \times 4 = 240$
$SA = 2(60 + 40 + 24) = 2(124) = 248$
A cylinder has $r=5$ and $h=12$. Find the volume.
$$V = \pi(5)^2(12) = 300\pi \approx 942.48$$
Find the volume of a sphere with radius 6.
$$V = \frac{4}{3}\pi(6)^3 = \frac{4}{3}\pi(216) = 288\pi \approx 904.78$$
A cone has $r = 4$ and $h = 9$. Find the volume.
$$V = \frac{1}{3}\pi(4)^2(9) = \frac{1}{3}\pi(144) = 48\pi \approx 150.80$$
A cube has volume 343. Find the side length and surface area.
$s = \sqrt[3]{343} = 7$.
$SA = 6(7^2) = 294$.
Practice Problems
Show Answer Key
1. $120$
2. $96$
3. $90\pi \approx 282.74$
4. $972\pi \approx 3{,}053.63$
5. $96\pi \approx 301.59$
6. $2\pi(16) + 2\pi(28) = 88\pi \approx 276.46$
7. $72\pi \approx 226.19$ ft³
8. $s = 8$
9. $r = 5$; $SA = 100\pi \approx 314.16$
10. $500$ m³
11. $100\pi = \frac{1}{3}\pi(25)h \implies h = 12$
12. $2(48 + 36 + 12) = 192$
13. $V = \pi(100)(20) = 2000\pi \approx 6{,}283$ cm³ $\approx 6.28$ L
14. $\frac{1}{2} \cdot \frac{4}{3}\pi(512) = \frac{1024\pi}{3} \approx 1{,}072.33$
15. $2\pi r = 20\pi \implies r = 10$; $V = \frac{4}{3}\pi(1000) \approx 4{,}188.79$