Perimeter and Area
Perimeter and Area of Common Shapes
Perimeter measures the total distance around a shape, while area measures the space enclosed inside it. These two concepts are among the most practical in all of mathematics — you use them every time you buy fencing for a yard, paint a wall, or lay carpet in a room.
Each common shape — rectangles, triangles, parallelograms, trapezoids, and circles — has its own area formula, but they are all related. The area of a triangle is half the area of a rectangle, and the area of a trapezoid is the average of the two bases times the height.
This lesson covers perimeter and area formulas for all standard two-dimensional shapes, along with composite-figure problems that combine multiple shapes.
| Shape | Perimeter | Area |
|---|---|---|
| Rectangle | $P = 2l + 2w$ | $A = lw$ |
| Square | $P = 4s$ | $A = s^2$ |
| Triangle | $P = a + b + c$ | $A = \frac{1}{2}bh$ |
| Parallelogram | $P = 2a + 2b$ | $A = bh$ |
| Trapezoid | Sum of sides | $A = \frac{1}{2}(b_1 + b_2)h$ |
Find the area and perimeter of a rectangle with $l = 15$ cm, $w = 8$ cm.
$A = 15 \times 8 = 120$ cm²
$P = 2(15) + 2(8) = 46$ cm
Find the area of a triangle with base 14 and height 9.
$$A = \frac{1}{2}(14)(9) = 63$$
A trapezoid has parallel sides 10 and 16, with height 7. Find the area.
$$A = \frac{1}{2}(10 + 16)(7) = \frac{1}{2}(26)(7) = 91$$
A room is 12 ft × 15 ft. Carpet costs $\$4.50$ per square foot. Find the cost.
$A = 12 \times 15 = 180$ ft². Cost $= 180 \times \$4.50 = \$810$.
Circles
- Circumference: $C = 2\pi r = \pi d$
- Area: $A = \pi r^2$
Find the circumference and area of a circle with radius 7.
$C = 2\pi(7) = 14\pi \approx 43.98$
$A = \pi(7)^2 = 49\pi \approx 153.94$
A circular garden has diameter 20 m. Find the area.
$r = 10$. $A = \pi(10)^2 = 100\pi \approx 314.16$ m².
Practice Problems
Show Answer Key
1. $P = 64$; $A = 240$
2. $99$
3. $66$
4. Side $= 13$; $A = 169$
5. $10\pi \approx 31.42$
6. $r = 6$; $A = 36\pi \approx 113.10$
7. $144$
8. $P = 160$ ft; Cost $= \$1{,}320$
9. $\frac{1}{2}\pi(36) = 18\pi \approx 56.55$
10. Yes ($25 + 144 = 169$). $A = \frac{1}{2}(5)(12) = 30$
11. $2(100) + \pi(50) \approx 357.08$ m
12. Side $= 10$; $A = 100$
13. $\frac{\pi(8)^2}{8} = 8\pi \approx 25.13$ sq. in.
14. $\frac{\sqrt{3}}{4}(100) = 25\sqrt{3} \approx 43.30$
15. $l = 15$; $P = 2(15)+2(8) = 46$