Power Series & Taylor Series
Power Series & Taylor Series
A series of the form:
$$\sum_{n=0}^{\infty} c_n (x - a)^n$$
centered at $x = a$ with coefficients $c_n$.
$$L = \lim_{n\to\infty} \left|\frac{a_{n+1}}{a_n}\right|$$
If $L < 1$: converges. If $L > 1$: diverges. If $L = 1$: inconclusive.
$$f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!}(x-a)^n$$
When $a = 0$, this is a Maclaurin series.
$$e^x = \sum_{n=0}^{\infty} \frac{x^n}{n!} \qquad \sin x = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n+1}}{(2n+1)!}$$
$$\cos x = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n}}{(2n)!} \qquad \frac{1}{1-x} = \sum_{n=0}^{\infty} x^n, \; |x| < 1$$
Use the ratio test on $\sum \frac{n!}{3^n}$.
$$L = \lim \frac{(n+1)!/3^{n+1}}{n!/3^n} = \lim \frac{n+1}{3} = \infty$$
Since $L > 1$, the series diverges.
Write the first 4 nonzero terms of the Maclaurin series for $e^x$.
$$e^x \approx 1 + x + \frac{x^2}{2} + \frac{x^3}{6}$$
Find the radius of convergence: $\sum \frac{x^n}{n}$.
Ratio test: $L = \lim \frac{|x|^{n+1}/(n+1)}{|x|^n/n} = |x| \cdot \lim \frac{n}{n+1} = |x|$.
Converges when $|x| < 1$, so radius $R = 1$.
Practice Problems
Show Answer Key
1. $L = \lim \frac{1}{n+1} = 0 < 1$; converges
2. $x - \frac{x^3}{6} + \frac{x^5}{120}$
3. $1 - \frac{x^2}{2} + \frac{x^4}{24}$
4. $1 + 0.1 + 0.005 = 1.105$ (actual ≈ 1.10517)
5. $R = 2$ (ratio test: $|x/2| < 1$)
6. $L = \lim \frac{2}{n+1} = 0$; converges
7. $\sum \frac{f^{(n)}(3)}{n!}(x-3)^n$
8. $\sum_{n=0}^{\infty} x^n$, $|x| < 1$
9. $L = \lim \frac{(n+1)/5^{n+1}}{n/5^n} = 1/5$; converges
10. $x - \frac{x^2}{2} + \frac{x^3}{3} - \frac{x^4}{4}$
11. Inconclusive — need another test
12. $0.1 - \frac{(0.1)^3}{6} \approx 0.1 - 0.000167 = 0.09983$