Placement Test Practice — Orbital Mechanics
Placement Test Practice — Orbital Mechanics
This practice test covers all major topics in orbital mechanics: Newton's law of gravitation, circular orbits, Kepler's laws, escape velocity, Hohmann transfers, and the vis-viva equation. Each problem requires identifying the correct formula, setting up the calculation, and interpreting the physical significance of the result. These problems integrate concepts from multiple lessons — some require combining gravitational field calculations with orbital mechanics, or energy methods with the vis-viva equation.
Practice Test
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1. $r = 7371$ km. $v = \sqrt{\mu/r} = 7354$ m/s. $T = 2\pi r/v = 6296$ s $= 104.9$ min. Orbits/day $= 1440/104.9 = 13.7$.
2. Semi-sync: $T = 43200$ s. $r_2 = (\mu T^2/4\pi^2)^{1/3} = 26{,}561$ km. $r_1 = 6571$ km. $a_t = 16{,}566$ km. $\Delta v_1 = \sqrt{\mu(2/r_1-1/a_t)} - v_1 = 9521 - 7788 = 1733$ m/s. $\Delta v_2 = v_2 - \sqrt{\mu(2/r_2-1/a_t)} = 3873 - 2357 = 1516$ m/s. Total $= 3249$ m/s.
3. $r_p = 6771$ km, $r_a = 11371$ km. $a = 9071$ km. $e = (11371-6771)/(11371+6771) = 0.254$. $T = 2\pi\sqrt{a^3/\mu} = 8604$ s $= 143.4$ min. $v_p = \sqrt{\mu(2/r_p - 1/a)} = 8708$ m/s. $v_a = \sqrt{\mu(2/r_a - 1/a)} = 5190$ m/s.
4. $r = 6871$ km. $\varepsilon = 10500^2/2 - \mu/r = 5.51 \times 10^7 - 5.80 \times 10^7 = -2.9 \times 10^6$ J/kg. Bound (ellipse). $a = \mu/(2 \times 2.9 \times 10^6) = 6.87 \times 10^7$ m $= 68{,}700$ km.
5. $v_{\text{esc}} = \sqrt{2GM/R} = \sqrt{2 \times 6.674 \times 10^{-11} \times 3.978 \times 10^{30}/10^4} = \sqrt{5.31 \times 10^{16}} = 2.30 \times 10^8$ m/s. That's $v/c = 0.768$ — 77% of the speed of light! (Relativistic effects become significant.)
6. $r = 6371 + 547 = 6918$ km. $T = 2\pi\sqrt{r^3/\mu} = 5735$ s $= 95.6$ min.
7. $r_1 = 42157$ km, $r_2 = 41957$ km. $a_t = 42057$ km. These orbits are so close that $\Delta v$ is tiny: $\Delta v_1 \approx 0.73$ m/s, $\Delta v_2 \approx 0.73$ m/s. Total $\approx 1.5$ m/s.
8. $g = GM/R^2$ and $v_{\text{esc}} = \sqrt{2GM/R}$. $v_{\text{esc}}^2 = 2gR \Rightarrow R = v_{\text{esc}}^2/(2g) = (24000)^2/(2 \times 25) = 11{,}520{,}000$ m $= 11{,}520$ km.
9. $r_p = a(1-e) = 7000(0.95) = 6650$ km. Alt$_p = 6650 - 6371 = 279$ km. $r_a = a(1+e) = 7350$ km. Alt$_a = 979$ km.
10. $\mu = 4\pi^2 r^3/T^2 = 4\pi^2 (6.711 \times 10^8)^3/(3.551 \times 86400)^2 = 1.192 \times 10^{28}/9.414 \times 10^{10} = 1.266 \times 10^{17}$ m³/s². Matches $\mu_J$. ✓