Word Problems with Equations
Translating Word Problems
Word problems are where algebra meets the real world. Translating a sentence like "the sum of a number and seven is twenty-three" into the equation x + 7 = 23 is the first and most important step — once the equation is set up correctly, the solving techniques you have already learned take over.
This lesson presents a variety of word problems that require setting up and solving linear equations. You will encounter age problems, consecutive-integer problems, distance-rate-time problems, and mixture problems.
The key to success is a methodical approach: define your variable, write the equation, solve, and then check your answer against the original problem statement.
| Phrase | Symbol |
|---|---|
| "is," "equals," "gives" | $=$ |
| "more than," "increased by" | $+$ |
| "less than," "decreased by" | $-$ |
| "times," "of," "product" | $\times$ |
| "at least" | $\ge$ |
| "at most," "no more than" | $\le$ |
Tom is 5 years older than twice Sara's age. Tom is 37. How old is Sara?
Let $s$ = Sara's age. $\;2s + 5 = 37 \;\Rightarrow\; 2s = 32 \;\Rightarrow\; s = 16$.
Three consecutive even integers sum to 72.
$n + (n+2) + (n+4) = 72 \;\Rightarrow\; 3n + 6 = 72 \;\Rightarrow\; n = 22$.
Integers: $22, 24, 26$.
Phone plan: $\$45$/mo + $\$0.10$/text. Budget $\le \$70$. Max texts?
$45 + 0.10t \le 70 \;\Rightarrow\; 0.10t \le 25 \;\Rightarrow\; t \le 250$.
Two angles are supplementary. One is $30°$ more than twice the other. Find both.
$x + (2x + 30) = 180 \;\Rightarrow\; 3x = 150 \;\Rightarrow\; x = 50$. Angles: $50°$ and $130°$.
A rectangle's length is 3 more than twice its width. Perimeter is 48. Dimensions?
$w + (2w + 3) + w + (2w + 3) = 48 \;\Rightarrow\; 6w + 6 = 48 \;\Rightarrow\; w = 7$.
Width $= 7$, Length $= 17$.
Practice Problems
Show Answer Key
1. $2x + 7 = 25$; $x = 9$
2. $35, 36, 37$
3. $50 + 30m > 260$; after month 7
4. $x + (2x - 15) = 90$; $35°$ and $55°$
5. $35 + 0.20m \le 100$; $m \le 325$ mi
6. Son $= 5$, Father $= 20$
7. $21$ and $29$
8. $15$ cm
9. $\dfrac{75+82+88+x}{4} \ge 80$; $x \ge 75$
10. $15$ quarter-miles $= 3.75$ miles