Simple & Compound Interest
Simple & Compound Interest
$$I = Prt, \qquad A = P(1 + rt)$$
$P$ = principal, $r$ = annual rate (decimal), $t$ = time in years, $A$ = accumulated amount.
$$A = P\left(1 + \frac{r}{n}\right)^{nt}$$
$n$ = compounding periods per year. As $n \to \infty$:
$$A = Pe^{rt}$$
$$\text{EAR} = \left(1 + \frac{r}{n}\right)^n - 1$$
The true annual yield accounting for compounding.
Find the simple interest on $\$5{,}000$ at $4\%$ for 3 years.
$I = 5000(0.04)(3) = \$600$. $A = \$5{,}600$.
Find the compound amount of $\$2{,}000$ at $6\%$ compounded quarterly for 5 years.
$A = 2000(1 + 0.06/4)^{20} = 2000(1.015)^{20} \approx \$2{,}693.71$.
Find the EAR for $8\%$ compounded monthly.
$\text{EAR} = (1 + 0.08/12)^{12} - 1 \approx 0.0830 = 8.30\%$.
Practice Problems
Show Answer Key
1. $I = 3000(0.05)(2) = \$300$
2. $A = 1000(1.01)^{40} \approx \$1{,}488.86$
3. $5\%$ monthly: EAR = $5.12\%$ > $5.1\%$; compounded is better
4. $(1.01)^{12}-1 \approx 12.68\%$
5. $10000 e^{0.24} \approx \$12{,}712.49$
6. $2 = 1.06^t$; $t = \ln 2/\ln 1.06 \approx 11.9$ years
7. $t = 1.5$; $A = 700(1+0.035 \cdot 1.5) = \$736.75$
8. $P = 5000/(1+0.04/12)^{36} \approx \$4{,}435.27$
9. $72/9 = 8$ years
10. $6\%$ semi: EAR $= 6.09\%$; $5.9\%$ daily: EAR $\approx 6.08\%$; $6\%$ semi wins
11. $A = 4000(1.05)^4 \approx 4862.03$; interest $\approx \$862.03$
12. $e^{0.10}-1 \approx 10.52\%$