Circles & Parabolas
Circles & Parabolas
A circle with center $(h,k)$ and radius $r$:
$$(x-h)^2 + (y-k)^2 = r^2$$
A parabola is the set of all points equidistant from a fixed point (focus) and a fixed line (directrix).
Vertical axis: $(x-h)^2 = 4p(y-k)$, focus at $(h, k+p)$.
Horizontal axis: $(y-k)^2 = 4p(x-h)$, focus at $(h+p, k)$.
To convert $x^2 + y^2 + Dx + Ey + F = 0$ to standard form, group and complete the square for each variable.
Find the center and radius: $x^2 + y^2 - 6x + 4y - 12 = 0$.
$(x^2-6x+9)+(y^2+4y+4) = 12+9+4$
$(x-3)^2+(y+2)^2 = 25$. Center $(3,-2)$, $r = 5$.
Find the vertex, focus, and directrix of $y = \frac{1}{8}x^2$.
$x^2 = 8y$, so $4p = 8$, $p = 2$. Vertex $(0,0)$, focus $(0,2)$, directrix $y = -2$.
Write the equation of a circle with center $(-1,3)$ and radius $4$.
$$(x+1)^2 + (y-3)^2 = 16$$
Practice Problems
Show Answer Key
1. Center $(2,-1)$, $r = 3$
2. $x^2+y^2=49$
3. $(x+1)^2+(y-4)^2 = 9$. Center $(-1,4)$, $r=3$.
4. Vertex $(0,0)$, $4p=12$, $p=3$; focus $(0,3)$
5. Vertex $(-2,1)$, $p=-2$; focus $(-4,1)$; opens left
6. $x^2 = 12y$
7. $y = 1$ (since $p = -1$, directrix is $y = -p = 1$)
8. $x^2 = 4py$; at edge: $5^2 = 4p(2)$; $p = 25/8 = 3.125$ ft
9. $r = \sqrt{50} = 5\sqrt{2}$
10. $4p = 16 > 0$, opens up
11. $r = \sqrt{9+16} = 5$; $x^2+y^2=25$
12. Circle (both $x^2$ and $y^2$ with same coefficient)