Complex Roots & Applications
Complex Roots & Applications
The $n$ distinct $n$th roots of $z = r\operatorname{cis}\theta$ are:
$$w_k = r^{1/n} \operatorname{cis}\left(\frac{\theta + 2\pi k}{n}\right), \quad k = 0, 1, \ldots, n-1$$
Every polynomial of degree $n \geq 1$ with complex coefficients has exactly $n$ roots (counted with multiplicity) in $\mathbb{C}$.
The $n$th roots of $1$ are $w_k = \operatorname{cis}\left(\frac{2\pi k}{n}\right)$ for $k = 0,1,\ldots,n-1$. They are equally spaced on the unit circle.
Find the square roots of $i$.
$i = \operatorname{cis}(\pi/2)$, $r = 1$, $n = 2$.
$w_0 = \operatorname{cis}(\pi/4) = \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i$
$w_1 = \operatorname{cis}(5\pi/4) = -\frac{\sqrt{2}}{2} - \frac{\sqrt{2}}{2}i$
Find all cube roots of $8$.
$8 = 8\operatorname{cis}(0)$. $r^{1/3} = 2$.
$w_0 = 2\operatorname{cis}(0) = 2$
$w_1 = 2\operatorname{cis}(2\pi/3) = -1 + \sqrt{3}i$
$w_2 = 2\operatorname{cis}(4\pi/3) = -1 - \sqrt{3}i$
Solve $x^2 + 2x + 5 = 0$.
$$x = \frac{-2 \pm \sqrt{4-20}}{2} = \frac{-2 \pm \sqrt{-16}}{2} = \frac{-2 \pm 4i}{2} = -1 \pm 2i$$
Practice Problems
Show Answer Key
1. $\pm i$
2. $-2$, $1+\sqrt{3}i$, $1-\sqrt{3}i$
3. $1, i, -1, -i$
4. $x = \pm 2i$
5. $x = 3 \pm 2i$
6. $\pm 5i$
7. $5$
8. $1$, $-\frac{1}{2}+\frac{\sqrt{3}}{2}i$, $-\frac{1}{2}-\frac{\sqrt{3}}{2}i$
9. $2-i$ (complex conjugate root theorem)
10. $x = \frac{-1 \pm \sqrt{-3}}{2} = -\frac{1}{2} \pm \frac{\sqrt{3}}{2}i$
11. $-4i = 4\operatorname{cis}(3\pi/2)$; roots: $2\operatorname{cis}(3\pi/4)$ and $2\operatorname{cis}(7\pi/4)$, i.e. $-\sqrt{2}+\sqrt{2}i$ and $\sqrt{2}-\sqrt{2}i$
12. $5$ (counting multiplicity)